x^3/4(1+x)=x^7/4+x^3/4

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Solution for x^3/4(1+x)=x^7/4+x^3/4 equation:


x in (-oo:+oo)

((x^3)/4)*(x+1) = (x^7)/4+(x^3)/4 // - (x^7)/4+(x^3)/4

((x^3)/4)*(x+1)-((x^7)/4)-((x^3)/4) = 0

1/4*x^3*(x+1)+(-x^7)/4+(-x^3)/4 = 0

(1/4*4*x^3*(x+1))/4+(-x^7)/4+(-x^3)/4 = 0

1/4*4*x^3*(x+1)-x^7-x^3 = 0

x^4-x^7+x^3-x^3 = 0

x^4-x^7 = 0

x^4-x^7 = 0

x^4*(1-x^3) = 0

-1*x^3 = -1 // : -1

x^3 = 1

x^3 = 1 // ^ 1/3

x = 1

x^4*(x-1) = 0

(x^4*(x-1))/4 = 0

(x^4*(x-1))/4 = 0 // * 4

x^4*(x-1) = 0

( x-1 )

x-1 = 0 // + 1

x = 1

( x^4 )

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x in { 1, 0 }

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